Laser Cutting Unit

I'm going into Infantry and wear glasses, when should I get laser corrective surgery, or should I at all?

Glasses aren't so bad, and some of the Wiley-X goggles I've looked at online can be tailored to my prescription. I've got astigmatism too with my near-sightedness, but it's all correctable to 20/20. I know there are a lot of risk with laser corrective surgery, and with my case with astigmatism, it's even riskier to get a perfect cut, so I still might have to wear glasses after getting the laser surgery.

I was thinking about just sticking with my glasses and getting those Wiley-X prescriptions for combat goggles once I'm deployed to my unit. I think that's the best bet, what do you guys think? I guess having perfect eyes would help me quality on the shooting range better when I'm at boot camp, but what can you do right?

Just wear BCG. They are safer.

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IDI Laser Sei Paper Blaster

What is the amplitude of the magnetic field produced?

High power lasers in factories are used to cut
through cloth and metal. One such laser has a
beam diameter of 0.998 mm and generates an
electric field at the target having an amplitude
0.158 MV/m.
The speed of light is 2.99792 × 108 m/s
the permeability of free space is 4π × 10−7 T · N/A.
What is the amplitude of the magnetic field
produced?
Answer in units of T.
What is the intensity of the laser?
Answer in units of W/m2.

What is the power dissipated?
Answer in units of W.

If E, H are intensities of Electric and Magnetic fields, in free space
Intrinsic impedance (Eta)
Eta = sqrt (E/H)
= 120 π
Power = E X H {as per Poynting theorem}
Magnetic intensity B
B = (mu) H
where (mu) = 4π x 10^-7 T.N/A.

H = E /(Eta)^2
= 0.158 x 10^6 / 14400π^2
B = (mu)H
= (4π x 10^-7)x(0.158 x 10^6 / 14400π^2)
= 1.58 / 3600 π
P = |E X H| Watts
= EH
= (0.158 x 10^6 / 120 π)^2
= 419108016.8 W
Intensity for Area, A
= P / A
= (0.158 x 10^6 / 120 π)^2 / π (0.998 x 10^-3)^2
= (0.158 x 10^6 / 120)^2 π(0.998 x 10^-3)^2
= (0.158 x 10^6 / 120 / 0.998 x 10^-3)^2 x π
= 7.874 x 10^16 W/m^2.
Comment : When beam diameter is given its intensity is not uniform across it and zero just outside it or what is called in common parlance as 'rectangular pulse' distribution. the distribution across the beam intensity is Gaussian in nature and the figure refers to where the Gaussian distribution falls off to (e^-2) value. in that case Intensity is obtained by integrating the power (Peak power at the center or 'bore sight') over a 2 dimensional (because beam cross section is a circle, 2 dimensional) Gaussian distribution.